Tkinter: How To Check Which Button Was Clicked With One Function?

I've been messing around with Tkinter and came up with this: from tkinter import * root = Tk() def red_color_change(): color_label.configure(fg='red') def blue_color_change

Solution 1:

Why not use lambda expression?

def color_change(color):
    color_label.configure(fg=color)

red_button = Button(root, text="Red", fg="red", font="Arial, 20")
red_button.grid(row=0, column=0)
red_button.bind('<Button-1>', lambda e: color_change('red'))

blue_button = Button(root, text="Blue", fg="blue", font="Arial, 20")
blue_button.grid(row=0, column=1)
blue_button.bind('<Button-1>', lambda e: color_change('blue'))

This will do.

Solution 2:

You can use true/false, or numbers (to provide another way).

def color_change(which): #can be integer or booleanifwhich == 1: #can be changed to true
        color_label.configure(fg='red')
    elifwhich == 2: #can be changed to false
        color_label.configure(fg='blue')

red_button = Button(root, text="Red", fg = "red", font="Arial, 20", command = lambda: color_change(1))

blue_button = Button(root, text="Blue", fg = "blue", font="Arial, 20", command = lambda: color_change(2))

Though using integers is better because you can support many more colors (not just 2, with true/false)

Solution 3:

You can simplify your program to use only one button, and one function, to toggle the color:

import tkinter as tk


def toggle_color():
    global color_index
    color_index = (color_index + 1) % 2
    color_label.configure(fg=colors[color_index])


if __name__ == '__main__':

    root = tk.Tk()

    colors = ['blue', 'red']
    color_index = 0

    toggle_button = tk.Button(root, text="toggle", fg="black", font="Arial, 20",
                              command=toggle_color)
    toggle_button.grid(row=0, column=0)

    color_label = tk.Label(root, text="Color", font="Arial, 20")
    color_label.grid(row=1, column=0)

    root.mainloop()