How Do I Split A String And Keep The Separators Using Python Re Library?

Here is my code: import re string = r'('Option A' | 'Option B') & ('Option C' | 'Option D')' word_list = re.split(r'[\(.\)]', string) -> ['', ''Option A' | 'Option B'', ' &a

Solution 1:

You can use re.findall to capture each parenthesis group:

import re
string = r"('Option A' | 'Option B') & ('Option C' | 'Option D')"
pattern = r"(\([^\)]+\))"
re.findall(pattern, string)
# ["('Option A' | 'Option B')", "('Option C' | 'Option D')"]

This also works with re.split

re.split(pattern, string)
# ['', "('Option A' | 'Option B')", ' & ', "('Option C' | 'Option D')", '']

If you want to remove empty elements from using re.split you can:

[s for s in re.split(pattern, string) if s]
# ["('Option A' | 'Option B')", ' & ', "('Option C' | 'Option D')"]

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How the pattern works:

• ( begin capture group
• \( matches the character ( literally
• [^\)]+ Match between one and unlimited characters that are not )
• \) matches the character ) literally
• ) end capture group